Calculus I · Limits and Continuity · lesson

Epsilon-Delta Proofs for Quadratic Functions

Concept

Learning objectives

Use a preliminary restriction such as xa<1|x-a|<1 to bound a factor that depends on xx; choose δ\delta as the minimum of two requirements.

Nonlinear Functions: Controlling an Extra Factor

For a quadratic, factoring the output error creates an extra factor involving xx.

Worked example
Show worked solution

We need to make

x24|x^2-4|

small. Factor:

x24=x2x+2.|x^2-4|=|x-2||x+2|.

The first factor is controlled by δ\delta, but x+2|x+2| still depends on xx. First impose the simple restriction

x2<1.|x-2|<1.

Then

1<x<3,1<x<3,

so

3<x+2<5,3<x+2<5,

and therefore

x+2<5.|x+2|<5.

Now

x24=x2x+2<5x2.|x^2-4|=|x-2||x+2|<5|x-2|.

To make this less than ε\varepsilon, require

x2<ε5.|x-2|<\frac\varepsilon5.

We need both restrictions, so choose

δ=min{1,ε5}.\boxed{\delta=\min\left\{1,\frac\varepsilon5\right\}}.

Now write the forward proof. Let ε>0\varepsilon>0, and choose the δ\delta above. If

0<x2<δ,0<|x-2|<\delta,

then x2<1|x-2|<1, so x+2<5|x+2|<5. Also, x2<ε/5|x-2|<\varepsilon/5. Hence

x24=x2x+2<5(ε5)=ε.|x^2-4| =|x-2||x+2| <5\left(\frac\varepsilon5\right) =\varepsilon.

Therefore,

limx2x2=4.\boxed{\lim_{x\to2}x^2=4}.
Concept

The minimum notation means, "Use whichever restriction is smaller." If ε/5\varepsilon/5 is tiny, use it. If ε/5\varepsilon/5 is larger than 11, keep the local bound 11. Both jobs must be done at once.

Worked example

A shifted square

Prove

limx1x2=1.\lim_{x\to1}x^2=1.
Show worked solution

Factor the output error:

x21=x1x+1.|x^2-1|=|x-1||x+1|.

If x1<1|x-1|<1, then 0<x<20<x<2, so x+1<3|x+1|<3. Therefore,

x21<3x1.|x^2-1|<3|x-1|.

Choose

δ=min{1,ε3}.\boxed{\delta=\min\left\{1,\frac\varepsilon3\right\}}.

Then

x21<3δε.|x^2-1|<3\delta\le\varepsilon.

After the explanation

Use the section idea

Reading lens

How small must the input window be to force every allowed output into the requested tolerance band?

Mental model

Epsilon sets the demanded vertical accuracy; delta is the horizontal promise you choose so every permitted nearby input meets that demand.

Decision

Work backward from the desired output inequality, isolate an input-distance bound, then state a positive delta that is no larger than that bound.

Common trap

A proof must control every eligible input in the punctured window; checking examples or choosing delta after seeing the input is not enough.

Check yourself

Formal understanding means you can translate between bands, inequalities, and words, then verify the implication from delta to epsilon in forward order.

Source & rights

Original instruction with traceable references.

The exposition is original. No Active Calculus exercise is reproduced verbatim. Public-domain examples were modernized and recomposed when used as inspiration.

The verified handoff declares original composition and requires owner provenance review. BetterGrades-original material remains separate from public-domain references; no source textbook PDF is published here.

Vocab
Limit
Math glossaryLimit
limxaf(x)=L\lim_{x\to a}f(x)=L

The value a function approaches as its input approaches a target.

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Function
Math glossaryFunction
y=f(x)y=f(x)

A rule or relation assigning exactly one output to each allowed input.

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Continuity
Math glossaryContinuity
limxaf(x)=f(a)\lim_{x\to a}f(x)=f(a)

At a point, the function value exists and equals the limit there.

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Domain
Math glossaryDomain
domf\operatorname{dom}f

The set of permitted input values.

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Math glossary