Calculus I · Limits and Continuity · practice

Trigonometric Limit Practice Problems

Visual study stop

Read the picture before the symbols

Pause at each graph long enough to say what the input is doing, what the output is doing, and which feature supports the next mathematical decision.

Graph of sin(x) divided by x with an open point at (0, 1).
Read this graph as text

The sine-over-x limit. The even function y = sin(x) divided by x is drawn from approximately negative 2 pi to 2 pi in two explicit branches that stop at zero. An open circle at (0, 1) marks the missing formula value. A dashed horizontal guide marks y = 1, and both branches approach that guide as x approaches zero.

The two solid branches stop at an open circle, and a dashed horizontal guide with text marks y = 1.

Why it matters: Show graphically that sin(x)/x approaches 1 from both sides even though the displayed formula is undefined at zero.

Anchor every rewrite to the fundamental shape

The open point marks an undefined quotient at zero while the graph approaches one from both sides. In each exercise, rewrite until the same angle appears in the sine and its denominator.

Section 3 Exercises

A. Squeeze Theorem

Exercise 1

If −x4≤f(x)≤x4-x^4\le f(x)\le x^4 near zero, find lim⁡x→0f(x)\lim_{x\to0}f(x).

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00.

Answer 1 from the source-traced unit appendix.
Exercise 2

If 2−x2≤g(x)≤2+x22-x^2\le g(x)\le2+x^2 near zero, find the limit.

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22.

Answer 2 from the source-traced unit appendix.
Exercise 3

Evaluate lim⁡x→0x3sin⁡(1/x)\lim_{x\to0}x^3\sin(1/x).

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00.

Answer 3 from the source-traced unit appendix.
Exercise 4

Evaluate lim⁡x→0x2cos⁡(7/x)\lim_{x\to0}x^2\cos(7/x).

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00.

Answer 4 from the source-traced unit appendix.
Exercise 5

Evaluate lim⁡x→0∣x∣sin⁡(4/x)\lim_{x\to0}|x|\sin(4/x).

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00.

Answer 5 from the source-traced unit appendix.
Exercise 6

Evaluate lim⁡x→0xcos⁡(1/x2)\lim_{x\to0}x\cos(1/x^2).

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00.

Answer 6 from the source-traced unit appendix.
Exercise 7

Suppose ∣f(x)∣≤5∣x−2∣|f(x)|\le5|x-2|. Find lim⁡x→2f(x)\lim_{x\to2}f(x).

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00.

Answer 7 from the source-traced unit appendix.
Exercise 8

Explain why boundedness of ff alone is not enough to conclude lim⁡x→0f(x)=0\lim_{x\to0}f(x)=0.

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A bounded function need not approach zero; for example, sin⁡(1/x)\sin(1/x) remains bounded but has no limit.

Answer 8 from the source-traced unit appendix.

B. Fundamental sine limits

Exercise 9

lim⁡x→0sin⁡xx\displaystyle\lim_{x\to0}\frac{\sin x}{x}

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11.

Answer 9 from the source-traced unit appendix.
Exercise 10

lim⁡x→0sin⁡(2x)x\displaystyle\lim_{x\to0}\frac{\sin(2x)}{x}

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22.

Answer 10 from the source-traced unit appendix.
Exercise 11

lim⁡x→0sin⁡(7x)3x\displaystyle\lim_{x\to0}\frac{\sin(7x)}{3x}

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7/37/3.

Answer 11 from the source-traced unit appendix.
Exercise 12

lim⁡x→0sin⁡(5x)sin⁡(2x)\displaystyle\lim_{x\to0}\frac{\sin(5x)}{\sin(2x)}

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5/25/2.

Answer 12 from the source-traced unit appendix.
Exercise 13

lim⁡x→0sin⁡(3x)sin⁡(8x)\displaystyle\lim_{x\to0}\frac{\sin(3x)}{\sin(8x)}

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3/83/8.

Answer 13 from the source-traced unit appendix.
Exercise 14

lim⁡t→0sin⁡(πt)t\displaystyle\lim_{t\to0}\frac{\sin(\pi t)}{t}

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π\pi.

Answer 14 from the source-traced unit appendix.
Exercise 15

lim⁡x→0xsin⁡(4x)\displaystyle\lim_{x\to0}\frac{x}{\sin(4x)}

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1/41/4.

Answer 15 from the source-traced unit appendix.
Exercise 16

lim⁡x→03xsin⁡(5x)\displaystyle\lim_{x\to0}\frac{3x}{\sin(5x)}

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3/53/5.

Answer 16 from the source-traced unit appendix.

C. Tangent and cosine limits

Exercise 17

lim⁡x→0tan⁡xx\displaystyle\lim_{x\to0}\frac{\tan x}{x}

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11.

Answer 17 from the source-traced unit appendix.
Exercise 18

lim⁡x→0tan⁡(4x)x\displaystyle\lim_{x\to0}\frac{\tan(4x)}{x}

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44.

Answer 18 from the source-traced unit appendix.
Exercise 19

lim⁡x→0tan⁡(3x)2x\displaystyle\lim_{x\to0}\frac{\tan(3x)}{2x}

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3/23/2.

Answer 19 from the source-traced unit appendix.
Exercise 20

lim⁡x→01−cos⁡xx\displaystyle\lim_{x\to0}\frac{1-\cos x}{x}

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00.

Answer 20 from the source-traced unit appendix.
Exercise 21

lim⁡x→01−cos⁡xx2\displaystyle\lim_{x\to0}\frac{1-\cos x}{x^2}

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1/21/2.

Answer 21 from the source-traced unit appendix.
Exercise 22

lim⁡x→01−cos⁡(4x)x2\displaystyle\lim_{x\to0}\frac{1-\cos(4x)}{x^2}

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88.

Answer 22 from the source-traced unit appendix.
Exercise 23

lim⁡x→0sin⁡2xx2\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}

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11.

Answer 23 from the source-traced unit appendix.
Exercise 24

lim⁡x→0sin⁡2(3x)x2\displaystyle\lim_{x\to0}\frac{\sin^2(3x)}{x^2}

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99.

Answer 24 from the source-traced unit appendix.

D. Mixed trigonometric limits

Exercise 25

lim⁡x→0sin⁡(2x)sin⁡(3x)x2\displaystyle\lim_{x\to0}\frac{\sin(2x)\sin(3x)}{x^2}

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66.

Answer 25 from the source-traced unit appendix.
Exercise 26

lim⁡x→0tan⁡(5x)sin⁡(2x)\displaystyle\lim_{x\to0}\frac{\tan(5x)}{\sin(2x)}

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5/25/2.

Answer 26 from the source-traced unit appendix.
Exercise 27

lim⁡x→01−cos⁡(2x)sin⁡2x\displaystyle\lim_{x\to0}\frac{1-\cos(2x)}{\sin^2x}

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22.

Answer 27 from the source-traced unit appendix.
Exercise 28

lim⁡x→0sin⁡(4x)xcos⁡x\displaystyle\lim_{x\to0}\frac{\sin(4x)}{x\cos x}

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44.

Answer 28 from the source-traced unit appendix.
Exercise 29

lim⁡x→0sin⁡xx(1+cos⁡x)\displaystyle\lim_{x\to0}\frac{\sin x}{x(1+\cos x)}

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1/21/2.

Answer 29 from the source-traced unit appendix.
Exercise 30

lim⁡x→0tan⁡x−sin⁡xx\displaystyle\lim_{x\to0}\frac{\tan x-\sin x}{x}

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00.

Answer 30 from the source-traced unit appendix.
Exercise 31

lim⁡x→01−cos⁡xxsin⁡x\displaystyle\lim_{x\to0}\frac{1-\cos x}{x\sin x}

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1/21/2.

Answer 31 from the source-traced unit appendix.
Exercise 32

lim⁡x→0sin⁡(3x)tan⁡(5x)\displaystyle\lim_{x\to0}\frac{\sin(3x)}{\tan(5x)}

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3/53/5.

Answer 32 from the source-traced unit appendix.

E. Reasoning and exam practice

Exercise 33

Explain why radians are required for lim⁡x→0sin⁡x/x=1\lim_{x\to0}\sin x/x=1.

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Radian measure equals unit-circle arc length; the geometric squeeze produces ratio 11 only in radians.

Answer 33 from the source-traced unit appendix.
Exercise 34

Derive lim⁡x→0tan⁡x/x=1\lim_{x\to0}\tan x/x=1 from the sine limit.

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tan⁡x/x=(sin⁡x/x)(1/cos⁡x)→1\tan x/x=(\sin x/x)(1/\cos x)\to1.

Answer 34 from the source-traced unit appendix.
Exercise 35

Derive lim⁡x→0(1−cos⁡x)/x2=1/2\lim_{x\to0}(1-\cos x)/x^2=1/2.

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Rationalize and use (sin⁡x/x)2/(1+cos⁡x)→1/2(\sin x/x)^2/(1+\cos x)\to1/2.

Answer 35 from the source-traced unit appendix.
Exercise 36

A student writes sin⁡(5x)=5x\sin(5x)=5x. Explain what is wrong and how to use the limit correctly.

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sin⁡(5x)\sin(5x) is not equal to 5x5x; only their ratio approaches 11 near zero.

Answer 36 from the source-traced unit appendix.
Exercise 37

Give a squeeze argument for lim⁡x→0x4sin⁡(1/x3)\lim_{x\to0}x^4\sin(1/x^3).

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Use −x4≤x4sin⁡(1/x3)≤x4-x^4\le x^4\sin(1/x^3)\le x^4; the limit is zero.

Answer 37 from the source-traced unit appendix.
Exercise 38

Create a trigonometric limit near zero whose value is 7/47/4.

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Example: lim⁡x→0sin⁡(7x)/(4x)=7/4\lim_{x\to0}\sin(7x)/(4x)=7/4.

Answer 38 from the source-traced unit appendix.

Answers begin in the referenced section.

After the explanation

Use the section idea

Reading lens

Can the expression be rewritten around a known small-angle limit, with every scaling factor accounted for?

Mental model

The fundamental sine limit is a reusable local shape: other trigonometric limits work when you expose that shape through identities and scaling.

Decision

Look for a bounded oscillation times a shrinking factor, or rewrite the expression into sine-over-angle factors whose arguments match their denominators.

Common trap

The sine function is not equal to its angle; their ratio merely approaches one near zero, and that statement requires radian measure.

Check yourself

Mastery means you can mark every scaling factor before simplifying and can explain where the Squeeze Theorem enters the argument.

Source & rights

Original instruction with traceable references.

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The verified handoff declares original composition and requires owner provenance review. BetterGrades-original material remains separate from public-domain references; no source textbook PDF is published here.

Vocab
Limit
Math glossaryLimit
lim⁡x→af(x)=L\lim_{x\to a}f(x)=L

The value a function approaches as its input approaches a target.

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Function
Math glossaryFunction
y=f(x)y=f(x)

A rule or relation assigning exactly one output to each allowed input.

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Continuity
Math glossaryContinuity
lim⁡x→af(x)=f(a)\lim_{x\to a}f(x)=f(a)

At a point, the function value exists and equals the limit there.

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Domain
Math glossaryDomain
dom⁡f\operatorname{dom}f

The set of permitted input values.

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Math glossary