BetterGrades Algebra · Unit A3 · Practice

Inequalities, Absolute Value, and Formulas: mixed practice

Inequalities, Absolute Value, and Formulas: mixed practice for Inequalities, Absolute Value, and Formulas, with an explicit attempt-first assessment blueprint.

Assessment

20 concrete questions

Suggested time: flexible minutes.

Grading boundary: deterministic where supported; symbolic equivalence server-side

Cumulative share: 30% prior units

Each question is fully authored and linked to a lesson skill. Detailed scoring criteria and worked solutions stay protected until a substantive attempt is submitted.

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Open-response checkA3.4

Explain why the method for interval notation and endpoint meaning is valid here and name one nearby problem where it would not apply.

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Open-response checkA3.4

Compare the conclusions of all three worked cases with this lesson outcome—Translate among inequalities, number-line graphs, and interval notation. Explain what remains invariant across them.

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Open-response checkA3.4

Exit check: solve and verify without referring to the displayed steps. Write x1x \le -1 or x>4x > 4 in interval notation and describe the endpoints.

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Open-response checkA3.4

Exit check: solve and verify without referring to the displayed steps. Translate [2,5)[-2, 5)(1,8](1, 8] into a compound inequality.

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Open-response checkA3.5

Classify the mathematical object and requested action in this lesson case: Solve 12x+3<9-1 \le 2x + 3 < 9 as one compound inequality.

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Open-response checkA3.5

State the central definition behind this outcome: Interpret and solve intersections and unions of conditions.

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Open-response checkA3.5

Before calculating, list every sign, endpoint, unit, grouping, or domain condition that can affect: Solve 12x+3<9-1 \le 2x + 3 < 9 as one compound inequality.

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Open-response checkA3.5

Explain why this opening move is valid: Subtract 33 from all three parts to obtain 42x<6-4 \le 2x < 6.

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Open-response checkA3.5

Solve 12x+3<9-1 \le 2x + 3 < 9 as one compound inequality.

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Open-response checkA3.5

Solve 3x273x - 2 \le 7 or 2x+5>132x + 5 > 13.

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Open-response checkA3.5

Solve4<23x11-4 < 2 - 3x \le 11

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Open-response checkA3.5

Verify the proposed result “2x<3,-2 \le x < 3, or [2,3)[-2, 3).” against the original statement.

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Open-response checkA3.5

Complete the calculation after “Solve the first inequality to obtain x3x \le 3.” in this problem: Solve 3x273x - 2 \le 7 or 2x+5>132x + 5 > 13.

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Open-response checkA3.5

Name and justify the most efficient first move, then solve: Solve 4<23x11-4 < 2 - 3x \le 11.

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Open-response checkA3.5

Compare the methods used in these two cases and identify the structural reason they differ: Solve 3x273x - 2 \le 7 or 2x+5>132x + 5 > 13. Solve 4<23x11-4 < 2 - 3x \le 11.

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Open-response checkA3.5

Create the representation most useful for checking this result: Solve 3x273x - 2 \le 7 or 2x+5>132x + 5 > 13. Use an inequality, interval notation, and a number-line description; each must show the same endpoints, inclusion, and direction.

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Open-response checkA3.5

A learner reports “2x<3,-2 \le x < 3, or [2,3)[-2, 3).” but omits the original-condition check. Explain the risk before deciding whether the result is supported.

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Open-response checkA3.5

Repair a solution that skips “Divide all three parts by 3-3 and reverse both order relations.” while solving: Solve 4<23x11-4 < 2 - 3x \le 11.

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Open-response checkA3.5

In this compound inequalities case, change one numerical value, solve the revised problem, and identify which parts of the original method still apply: Solve 12x+3<9-1 \le 2x + 3 < 9 as one compound inequality.

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Open-response checkA3.5

Connect the opening situation “Find values satisfying simultaneous minimum and maximum requirements.” to the algebraic structure used in the worked case. Define quantities and units before writing any equation.

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