BetterGrades Algebra · Unit A2 · Lesson

Equations with fractions and decimals

Solve equations with rational coefficients directly or by clearing denominators strategically.

Opening situation

Start here

Resolve a formula involving fractional rates.

Solve linear equations with fractions and decimals by choosing exact, efficient ways to clear denominators or decimal places.

Before this lesson

Prerequisite check

  1. Find the least common multiple of 44 and 66.
  2. Multiply 0.350.35 by 100100.
  3. Add 23\frac{2}{3} and 16\frac{1}{6}.
Lesson text

Explanation

Fractions and decimals do not change the logic of solving; they change which first step is efficient. Multiplying every term on both sides by the least common denominator clears fractions while preserving equality. The multiplier must reach every term, not only the terms with denominators.

Terminating decimals can be cleared by multiplying both sides by a suitable power of ten. This is an equality operation, not a decimal-point shortcut. Exact fraction arithmetic is often preferable to early rounding because rounding can change a solution.

After clearing the notation, solve the resulting integer-coefficient equation and check in the original form. When measurements are approximate, distinguish an exact algebraic result from a deliberately rounded reported value.

Fractions and decimals do not change the logic of a linear equation, but they can hide its structure. A common first move is to multiply every term on both sides by a useful nonzero factor. For fractional coefficients, the least common denominator clears all denominators. For terminating decimals, a power of ten can produce whole-number coefficients. This is an equality-preserving scale operation, not a deletion of fraction bars or decimal points.

The multiplier must reach every term. In x3+14=56,\frac{x}{3} + \frac{1}{4} = \frac{5}{6,} multiplying by 1212 gives 4x+3=104x + 3 = 10. Omitting the 14\frac{1}{4} term would change the equation. Writing parentheses around each side—12(x3+14)=12(56)12(\frac{x}{3} + \frac{1}{4}) = 12(\frac{5}{6})—makes distribution explicit. Original denominator restrictions remain active even after the visible denominators disappear.

Decimals can be kept exactly. Multiplying 0.4x1.25=2.750.4x - 1.25 = 2.75 by 100100 produces 40x125=275,40x - 125 = 275, but multiplying by 2020 would also work and may create smaller numbers. Alternatively, solving directly with decimals is valid if place value is handled accurately. Choose the path that minimizes arithmetic risk and keep full precision until the end.

A fraction in a model often carries units. If 34\frac{3}{4} hour at rate rr produces 4242 miles, then (34(\frac{3}{4} h)r =42= 42 mi and rr has units mileshour\frac{miles}{hour}. Multiplying both sides by 43\frac{4}{3} isolates rr and cancels hours appropriately. Unit analysis helps distinguish a coefficient from a constant and catches inverted rates.

Check in the original fractional or decimal equation, not only the cleared version. Clearing denominators can magnify an arithmetic slip, and rounded intermediate values can make a false equality appear close. Use exact fractions whenever possible, show the common multiplier, retain original restrictions, and substitute the exact result back before converting to a requested decimal approximation.

Equations with decimal coefficients may be solved in decimal form or converted to whole-number coefficients by multiplying every term on both sides by a power of ten. For 0.3x+1.2=2.7,0.3x + 1.2 = 2.7, multiplying the entire equation by 1010 gives 3x+12=273x + 12 = 27. The multiplication must reach every term; multiplying only the decimal terms changes the equation. The whole-number version often reduces calculator dependence and makes exact checking easier.

For fractional coefficients, multiply every term by the least common denominator of all numerical denominators. In x314=56,\frac{x}{3} - \frac{1}{4} = \frac{5}{6,} the LCD is 12,12, so 12(x3)12(14)=12(56),12(\frac{x}{3}) - 12(\frac{1}{4}) = 12(\frac{5}{6}), giving 4x3=104x - 3 = 10. Clearing denominators does not mean canceling terms across addition; it is distribution of one nonzero multiplier across both complete sides. Preserve any original denominator restrictions when variables later appear in denominators.

After clearing decimals or fractions, the new equation should be equivalent to the original, so either may be used for solving but the original should be used for the final check. Track multiplication with parentheses: 12(x314)=12(56)12(\frac{x}{3} - \frac{1}{4}) = 12(\frac{5}{6}) makes distribution visible. If every coefficient shares a common integer factor after clearing, divide the entire equation by that factor to reduce the numbers before isolating xx. Write the chosen LCD or power of ten explicitly so every transformed coefficient can be audited. Confirm carefully that no term on either side was skipped during complete distribution.

Method

Clear number formats without changing the equation

  1. Record denominator restrictions and identify the least useful common multiplier.
  2. Multiply every term on both sides by that nonzero factor.
  3. Solve the resulting equivalent equation with visible balance steps.
  4. Check the exact result in the original fractional or decimal equation.

Check: Substitution into the original form must produce exact equality before any requested rounding is applied.

Reference

Definitions and conditions

least common denominator
The least positive number divisible by every denominator in an equation.Multiplying every term by it clears all listed fractions.
clearing decimals
Multiplying both sides by a power of ten to obtain integer coefficients.Every term on both sides must receive the same factor.
exact value
A value represented without approximation, often as a fraction.Round only when the context requests an approximation.
clear denominators
Multiply every term in an equation by a common nonzero multiple of its denominators.Original denominator restrictions remain in force.
exact decimal
A terminating decimal used as its precise base-ten rational value rather than a rounded approximation.Avoid unnecessary rounding during solving.
Examples

Worked examples

Foundation

Solvex3+14=56\frac{x}{3} + \frac{1}{4} = \frac{5}{6}

  1. Use LCD 1212 and multiply every term by 1212.
  2. Obtain4x+3=104x+3=10
  3. Solve, then check4x=74x=7

Answerx=74x = \frac{7}{4}

Clearing denominators produces an equivalent integer equation. The least common denominator removes every fraction in one reversible scaling step.

Representation

Solve0.3x1.2=2.40.3x - 1.2 = 2.4

  1. Multiply every term by 1010.
  2. Solve3x12=243x-12=24
  3. Check0.3(12)1.2=2.40.3(12)-1.2=2.4

Answerx=12x = 12

A power of ten can remove terminating decimals cleanly. A power of ten is a convenience; the decimal equation remains exact before and after scaling.

Transfer

Solve2x15=x+43\frac{2x-1}{5} = \frac{x+4}{3}

  1. Multiply both sides by 1515.
  2. Obtain3(2x1)=5(x+4)3(2x-1)=5(x+4)
  3. Expand, solve, and verify.

Answerx=23x = 23

The LCD clears both compound numerators without cross-multiplication ambiguity. Checking the original form verifies the multiplier distribution and any denominator restrictions.

Practice

20 practice questions

Recall and read the structure

Warm-up

Question 1Retrieval · Foundation

Solvex4=7\frac{x}{4} = 7

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 2Retrieval · Foundation

Solvex5+2=8\frac{x}{5} + 2 = 8

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 3Concept · Standard

Solvex312=56\frac{x}{3} - \frac{1}{2} = \frac{5}{6}

Need a hint?

State what must remain true, then connect that condition to the equation.

Question 4Concept · Standard

Solvex4+x6=5\frac{x}{4} + \frac{x}{6} = 5

Need a hint?

State what must remain true, then connect that condition to the equation.

Build accuracy one step at a time

Core practice

Question 5Procedure · Standard

Solvex23=5\frac{x-2}{3} = 5

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 6Procedure · Standard

Solve2x+14=32\frac{2x+1}{4} = \frac{3}{2}

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 7Procedure · Mixed

Solve0.6x=4.20.6x = 4.2

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 8Procedure · Mixed

Solve0.25x+1.5=30.25x + 1.5 = 3

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 9Procedure · Standard

Solve1.2x0.4=2.01.2x - 0.4 = 2.0

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 10Procedure · Mixed

Solve0.03x+0.12=0.300.03x + 0.12 = 0.30

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 11Representation · Mixed

What multiplier clears denominators in x6+18=13\frac{x}{6} + \frac{1}{8} = \frac{1}{3}?

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Question 12Representation · Transfer

After multiplying x3+2=56\frac{x}{3} + 2 = \frac{5}{6} by 6,6, write the correct equation.

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Explain, compare, and diagnose

Represent and reason

Question 13Error Analysis · Mixed

A student rounds 23\frac{2}{3} to 0.670.67 before solving. Why is that risky?

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 14Transfer · Transfer

Solvex+12x13=4\frac{x+1}{2} - \frac{x-1}{3} = 4

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 15Modeling · Transfer

Check x=12x = 12 in 0.3x1.2=2.40.3x-1.2=2.4.

Need a hint?

Define the unknown and its units before writing the equation.

Question 16Exit · Standard

Solve and verify3x24=x+62\frac{3x-2}{4} = \frac{x+6}{2}

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Model, transfer, and verify

Finish strong

Question 17Transfer · Transfer

Solvex4x6=53\frac{x}{4} - \frac{x}{6} = \frac{5}{3}

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 18Modeling · Transfer

Solve 0.35x+1.2=4.70.35x + 1.2 = 4.7 using a whole-number equivalent equation.

Need a hint?

Define the unknown and its units before writing the equation.

Question 19Error Analysis · Mixed

Solve (25)(x3)=6(\frac{2}{5})(x - 3) = 6 and compare clearing fractions with using a reciprocal.

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 20Exit · Standard

A student multiplies x3+2=76\frac{x}{3} + 2 = \frac{7}{6} by 66 and writes 2x+2=72x + 2 = 7. Repair the distribution.

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Common mistakes

Error analysis

Wrong move: Multiplying by the LCD only affects fraction terms.

Why it fails: An equality operation must apply to every term on both sides.

Repair: Use grouping or annotate the multiplier across the full equation before simplifying.

Open-response checkA2.6

A student multiplies x3+2=76\frac{x}{3} + 2 = \frac{7}{6} by 66 and writes 2x+2=72x + 2 = 7. Repair the distribution.

Write a complete attempt before opening the response guide.

Attempt once to unlock the response guide

Complete a substantive attempt to unlock the protected solution and scoring criteria.

Before continuing

Exit check

  1. Solve (25)(x3)=6(\frac{2}{5})(x - 3) = 6 and compare clearing fractions with using a reciprocal.
  2. A student multiplies x3+2=76\frac{x}{3} + 2 = \frac{7}{6} by 66 and writes 2x+2=72x + 2 = 7. Repair the distribution.
Summary

What to remember

Clear fractions or decimals by multiplying every term on both sides by one useful factor.

  • Keep exact values through the algebra and verify in the original equation.

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