BetterGrades Algebra · Unit A2 · Lesson

Multiplication and division equations

Use reciprocals and equal scaling to isolate a variable, with explicit zero restrictions.

Opening situation

Start here

Recover a unit quantity from a scaled total.

Solve multiplication and division equations using reciprocal operations, with attention to zero restrictions.

Before this lesson

Prerequisite check

  1. Find the reciprocal of 35\frac{3}{5}.
  2. Evaluate 46-4 \cdot 6.
  3. Explain why division by zero is not defined.
Lesson text

Explanation

In a multiplication equation such as 7x=42,7x = 42, the coefficient 77 tells how xx is scaled. Dividing both sides by the nonzero coefficient reverses that scaling and preserves equality. Writing x=427x = \frac{42}{7} makes the inverse operation visible.

A division equation such as x5=8\frac{x}{5} = 8 can be read as one fifth of xx equals 88. Multiplying both sides by 55 clears the division. Fractions are handled the same way: multiplying by the reciprocal of a nonzero coefficient isolates the variable.

Zero is a structural boundary. Dividing by a coefficient is valid only when that coefficient is not zero. The equation 0x=50x = 5 has no solution, while 0x=00x = 0 is true for every xx; neither can be handled by dividing by zero.

In ax == b, multiplication by coefficient a is undone by division by a, provided a0a \ne 0. Dividing both sides by the same nonzero number preserves equality and gives x=bax = \frac{b}{a}. The nonzero condition is not optional: division by zero has no real-number value. Write the coefficient, including its sign, as part of the variable term. For 4x=20,-4x = 20, divide by 4-4 to obtain x=5x = -5.

A fraction coefficient can be undone by multiplying by its reciprocal. In (35)x=12,(\frac{3}{5})x = 12, multiply both sides by 53\frac{5}{3} to produce x=20x = 20. This is the same operation as dividing by 35,\frac{3}{5,} expressed in a form that cancels visibly. The coefficient must be nonzero, and the reciprocal must multiply the entire side. Estimating the scale helps: if three-fifths of xx is 12,x12, x should be larger than 1212.

Division equations can be rewritten as multiplication equations. In x7=3,\frac{x}{7} = -3, multiply both sides by 77 to obtain x=21x = -21. In 7x=3,\frac{7}{x} = -3, however, xx is in the denominator and the equation is not a one-step linear equation of the same form; multiplying by xx creates a restriction x0x \ne 0 and requires later checking. Reading factor and denominator structure prevents different equation types from being treated as identical.

The coefficient zero creates a classification problem rather than a division step. The equation 0x=00x = 0 is true for every real x, while 0x=50x = 5 is false for every real xx. Dividing by zero would hide this distinction. Before dividing, inspect the coefficient. This early habit prepares the learner to classify equations whose variables later cancel.

Units can clarify multiplicative equations. If 66 tickets cost $54\$54 at a constant price p, then 6p=$546p = \$54 and p=$9p = \$9 per ticket. Dividing dollars by tickets produces dollars per ticket. Substitute the result into the original model and confirm both number and units. A coefficient is often aa count, rate, or scale factor, and interpreting it makes the inverse operation more than symbol movement.

Multiplication and division equations are undone with reciprocal operations. If 7x=35,7x = 35, divide both sides by the nonzero coefficient 77. If x5=9,\frac{x}{5} = 9, multiply both sides by 55. The coefficient includes its sign, so 4x=20-4x = 20 requires division by 4-4 and gives x=5x = -5. Separating the sign from the magnitude during a prediction can prevent an answer with the wrong direction.

Fractional coefficients are often cleared by multiplying by their reciprocal. In (35)x=12,(\frac{3}{5})x = 12, multiplying both sides by 53\frac{5}{3} creates x=20x = 20. The reciprocal exists because 35\frac{3}{5} is nonzero. Alternatively, multiply by 55 and then divide by 33; both paths preserve equality and should agree. Choose the form with fewer opportunities for arithmetic error, then verify by reconstructing the original product or quotient.

A zero coefficient creates a special case rather than an ordinary division step. In 0x=0,0x = 0, every real xx works; in 0x=7,0x = 7, no real xx works. Dividing by zero is not permitted, so the instruction “divide by the coefficient” always carries a nonzero condition. Recognizing this boundary prepares the later classification of equations and prevents a forbidden operation from being hidden in an otherwise familiar procedure. A final check should therefore inspect both the candidate value and whether every operation used to obtain it was allowed.

Method

Undo a nonzero scale factor

  1. Identify the complete coefficient multiplying the variable, including sign and units.
  2. Confirm the coefficient is nonzero.
  3. Divide both sides by the coefficient or multiply by its reciprocal.
  4. Simplify, interpret units, and check in the original equation.

Check: Multiply the proposed value by the original coefficient and confirm that it reproduces the original right side exactly.

Reference

Definitions and conditions

coefficient
The numerical factor multiplying a variable.A nonzero coefficient can be undone by division.
reciprocal
A number that multiplies with a nonzero number to produce 11.Zero has no reciprocal.
zero-product boundary
The special behavior created when a variable's coefficient is zero.Check the resulting statement instead of dividing by zero.
coefficient equation
An equation of the form ax =b= b in which a scales the unknown.When a0,a \ne 0, the unique solution is x=bax = \frac{b}{a}.
zero coefficient
A coefficient equal to 0,0, making the variable term 00 for every input.The equation must be classified as always true or always false rather than divided by zero.
Examples

Worked examples

Foundation

Solve6x=27-6x = 27

  1. Divide both sides by 6-6.
  2. Simplifyx=276=92x = \frac{27}{-6} = -\frac{9}{2}
  3. Check6(92)=27-6(-\frac{9}{2}) = 27

Answerx=92x = -\frac{9}{2}

A negative coefficient reverses the sign of the quotient. Dividing by the full signed coefficient isolates the variable in one equality-preserving step.

Representation

Solvex4=7\frac{x}{-4} = 7

  1. Multiply both sides by 4-4.
  2. Simplifyx=28x = -28
  3. Check284=7\frac{-28}{-4} = 7

Answerx=28x = -28

Multiplication by the denominator clears division. The reciprocal is justified because its product with a nonzero fraction coefficient is 11.

Transfer

Solve(35)x=12(\frac{3}{5})x = 12

  1. Multiply both sides by the reciprocal 53\frac{5}{3}.
  2. Cancel (53)(35)(\frac{5}{3})(\frac{3}{5}) to 11.
  3. Simplify1253\frac{12\cdot 5}{3}

Answerx=20x = 20

A reciprocal undoes a nonzero fractional coefficient. Inspecting a zero coefficient prevents a forbidden division from erasing the equation’s true classification.

Practice

20 practice questions

Recall and read the structure

Warm-up

Question 1Retrieval · Foundation

Solve8x=568x = 56

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 2Retrieval · Foundation

Solve5x=35-5x = 35

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 3Concept · Standard

Solve12x=912x = -9

Need a hint?

State what must remain true, then connect that condition to the equation.

Question 4Concept · Standard

Solve0.4x=3.20.4x = 3.2

Need a hint?

State what must remain true, then connect that condition to the equation.

Build accuracy one step at a time

Core practice

Question 5Procedure · Standard

Solvex6=9\frac{x}{6} = 9

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 6Procedure · Standard

Solvex7=3\frac{x}{-7} = -3

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 7Procedure · Mixed

Solvex2.5=4\frac{x}{2.5} = 4

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 8Procedure · Mixed

Solvex34=8\frac{x}{\frac{3}{4}} = 8

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 9Procedure · Standard

Solve(23)x=14(\frac{2}{3})x = 14

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 10Procedure · Mixed

Solve(58)x=15(-\frac{5}{8})x = 15

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 11Representation · Mixed

Solve ax =b= b for xx when a0a \ne 0.

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Question 12Representation · Transfer

Analyze 0x=60x = 6.

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Explain, compare, and diagnose

Represent and reason

Question 13Error Analysis · Mixed

Analyze 0x=00x = 0.

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 14Transfer · Transfer

A student solves 4x=20-4x=20 as x=5x=5. Repair the sign.

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 15Modeling · Transfer

Check x=18x = 18 in x3=6\frac{x}{3} = 6.

Need a hint?

Define the unknown and its units before writing the equation.

Question 16Exit · Standard

Solve and verify(74)x=21(\frac{7}{4})x = -21

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Model, transfer, and verify

Finish strong

Question 17Transfer · Transfer

Solve 7x=35-7x = 35 and check the sign before calculating.

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 18Modeling · Transfer

Solve(49)y=14(-\frac{4}{9})y = 14

Need a hint?

Define the unknown and its units before writing the equation.

Question 19Error Analysis · Mixed

Classify 0z=00z = 0 and 0z=80z = -8.

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 20Exit · Standard

Five equal containers hold 17.517.5 liters total. Write and solve a coefficient equation with units.

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Common mistakes

Error analysis

Wrong move: Dividing both sides by the visible coefficient always works.

Why it fails: A coefficient may be zero, and division by zero is not defined.

Repair: Confirm the divisor is nonzero; if it is zero, analyze the resulting constant statement.

Open-response checkA2.3

Five equal containers hold 17.517.5 liters total. Write and solve a coefficient equation with units.

Write a complete attempt before opening the response guide.

Attempt once to unlock the response guide

Complete a substantive attempt to unlock the protected solution and scoring criteria.

Before continuing

Exit check

  1. Classify 0z=00z = 0 and 0z=80z = -8.
  2. Five equal containers hold 17.517.5 liters total. Write and solve a coefficient equation with units.
Summary

What to remember

Undo a nonzero coefficient by division or multiplication by its reciprocal.

  • Never divide by zero; analyze zero-coefficient equations as true or false statements.

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