BetterGrades Algebra · Unit A10 · Lesson

Direct, inverse, and joint variation

Translate proportional structures into formulas with a constant parameter.

Opening situation

Start here

Model how one quantity changes when another doubles or halves.

Use the opening situation and three distinct, fully solved cases to learn direct, inverse, and joint variation as a connected mathematical idea rather than a memorized slogan.

Before this lesson

Prerequisite check

  1. State the earlier definition or operation most directly connected to: Translate proportional structures into formulas with a constant parameter.
  2. Classify the object in the worked prompt before choosing an operation: The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.
  3. Name the check you would use to reject an answer with the wrong sign, domain, units, endpoint, or graph behavior.
Lesson text

Explanation

Translate proportional structures into formulas with a constant parameter. The lesson is about a particular mathematical decision, not a keyword or a decorative notation pattern. In direct, inverse, and joint variation, first identify the object being studied and the information the answer must contain. Then mark the conditions that cannot be lost: these may include sign, endpoint inclusion, grouping, units, denominator restrictions, real-number domain, or the difference between an exact value and an approximation. A useful solution explains why its first move matches that structure.

Model how one quantity changes when another doubles or halves. This opening is useful because it forces the quantities to acquire meaning before symbols compress them. Name the changing and fixed quantities, define any reference value or input interval, and decide what would count as a plausible result. An estimate, sign prediction, graph feature, or domain statement made before calculation becomes an independent check afterward. Without that prediction, algebra can be internally tidy while answering the wrong contextual question.

Consider the worked problem: The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers. Begin with this justified move: Write t=knt = \frac{k}{n}. Next, use 10=k610 = \frac{k}{6} to find k=60k = 60 worker-hours. Finally, evaluate t=6015t = \frac{60}{15} and interpret the units. Each line should preserve the relevant relationship or deliberately produce candidates that are later tested. Skipping the middle line may hide the exact sign, factor, interval, or restriction on which the conclusion depends.

The result is 44 hours. Inverse variation keeps the product nt constant while one quantity rises and the other falls. A textbook answer does not stop at the last symbol. It states what the result means, includes units or set notation where required, and distinguishes a verified solution from a candidate. The original statement remains the final authority whenever the method includes a one-way operation, denominator clearing, squaring, graph estimation, regression, or numerical approximation.

Show the original restriction set, factored form, simplified form, and graph features such as holes or asymptotes when relevant. Changing representation is useful only when it exposes information rather than duplicating decoration. A table may reveal constant difference or ratio, a graph may reveal intersections or extrema, interval notation may compress a truth set, and factored or vertex form may expose a feature hidden in expanded form. The second representation must preserve the same values, restrictions, units, endpoints, and conclusions as the first.

A rational expression is a quotient of polynomials and inherits every value excluded by its original denominator. Restrictions are part of the expression’s identity and survive simplification. Cancellation applies to common factors in a product, not to terms separated by addition or subtraction. Factoring first reveals whether a legitimate common factor exists. For direct, inverse, and joint variation, connect this principle directly to the stated outcome: Translate proportional structures into formulas with a constant parameter.

Rational operations follow fraction structure. Multiply and divide by factoring and using reciprocals, but add and subtract only after creating a common denominator. The least common denominator contains every irreducible factor at the greatest power required. Complex rational expressions become ordinary rational expressions when numerator and denominator are multiplied by a common LCD, which is multiplication by a carefully chosen form of one. For direct, inverse, and joint variation, connect this principle directly to the stated outcome: Translate proportional structures into formulas with a constant parameter.

Clearing denominators in an equation produces candidate solutions because the multiplier can be zero at excluded inputs. Every candidate must be checked in the original equation. Rational inequalities also use zeros and restrictions as critical values, but restrictions are never included. On graphs, a canceled factor can create a hole, while an uncanceled denominator factor can create a vertical asymptote; the algebra explains the distinction. For direct, inverse, and joint variation, connect this principle directly to the stated outcome: Translate proportional structures into formulas with a constant parameter.

A common failure is: Cancelling terms across addition or erasing a restriction after a factor cancels. Cancellation divides an entire numerator and denominator by a common nonzero factor; separate terms are not factors. The repair is concrete: Factor completely, state restrictions first, cancel only common factors, and check candidates in the original expression or equation. In the worked case, use the repair by checking “44 hours.” against the original problem rather than trusting that the final line merely looks familiar.

Inverse variation keeps the product nt constant while one quantity rises and the other falls. That conclusion is the bridge to the next lesson: the method matters because it preserves meaning while the representation changes. A durable summary therefore has four parts—classify the object, state the conditions, carry out one justified step at a time, and perform an independent check. If any of those parts is missing, return to the original quantities before adding more algebra.

Method

Solve direct, inverse, and joint variation from structure

  1. Write t=knt = \frac{k}{n}.
  2. Use 10=k610 = \frac{k}{6} to find k=60k = 60 worker-hours.
  3. Evaluate t=6015t = \frac{60}{15} and interpret the units.

Check: Substitute a permitted test value into original and simplified forms, and test every equation candidate in the original denominators.

Reference

Definitions and conditions

Direct, inverse, and joint variation
Translate proportional structures into formulas with a constant parameter.Use the term only when the object satisfies the structural and domain conditions developed in this lesson.
domain restriction
An input excluded because it makes an original denominator zero.The restriction remains even when the corresponding factor later cancels.
least common denominator
A product containing every denominator factor at its greatest required power.Each denominator must divide the LCD exactly.
rational equation candidate
A value obtained after denominator clearing that may or may not solve the original equation.Every candidate must satisfy all original restrictions and the original equality.
Figure for Direct, inverse, and joint variation: Inverse-curve preview.
Read this graph as text

Direct, inverse, and joint variation · Inverse-curve preview.. Figure for Direct, inverse, and joint variation: Inverse-curve preview. Read the labels in order, identify what is held fixed and what changes, and compare the representations before drawing a conclusion. The figure is a deterministic BetterGrades rendering of storyboard brief A10.9-V3.

Meaning is carried by written labels, position, line style, and shape; color is supplementary.

Why it matters: Use the visible structure in “Inverse-curve preview.” to connect the opening context to the lesson outcome: Translate proportional structures into formulas with a constant parameter.

Direct, inverse, and joint variation · Figure A10.9-V3

Inverse-curve preview.

Examples

Worked examples

Worked Example 1

The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.

  1. Write t=knt = \frac{k}{n}.
  2. Use 10=k610 = \frac{k}{6} to find k=60k = 60 worker-hours.
  3. Evaluate t=6015t = \frac{60}{15} and interpret the units.

Answer44 hours.

Inverse variation keeps the product nt constant while one quantity rises and the other falls.

Worked Example 2

The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7.

  1. Write d=d = kt.
  2. Use 150=3k150 = 3k to find k=50k = 50.
  3. Evaluated=50(7)d = 50(7)

Answerd=50td = 50t; d=350d = 350.

The constant of variation carries the rate units.

Worked Example 3

zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

  1. Write z=kxywz = \frac{kxy}{w}.
  2. Use 12=k(3)(8)412 = \frac{k(3)(8)}{4} to obtain k=2k = 2.
  3. Evaluatez=2(5)(6)10z = \frac{2(5)(6)}{10}

Answerz=6z = 6

A combined-variation model records exactly which quantities multiply and which divide.

Practice

20 practice questions

Recall and read the structure

Warm-up

Question 1Retrieval · Foundation

Classify the mathematical object and requested action in this lesson case: The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 2Retrieval · Foundation

State the central definition behind this outcome: Translate proportional structures into formulas with a constant parameter.

Need a hint?

Recall the named definition or perform a direct substitution before choosing an operation.

Question 3Concept · Standard

Before calculating, list every sign, endpoint, unit, grouping, or domain condition that can affect: The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.

Need a hint?

State what must remain true, then connect that condition to the equation.

Question 4Concept · Standard

Explain why this opening move is valid: Write t=knt = \frac{k}{n}.

Need a hint?

State what must remain true, then connect that condition to the equation.

Build accuracy one step at a time

Core practice

Question 5Procedure · Standard

The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 6Procedure · Standard

The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 7Procedure · Mixed

zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 8Procedure · Mixed

Verify the proposed result “44 hours.” against the original statement.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 9Procedure · Standard

Complete the calculation after “Write d=d = kt.” in this problem: The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 10Procedure · Mixed

Name and justify the most efficient first move, then solve: zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Need a hint?

Write one equality-preserving step at a time and keep signs and grouping visible.

Question 11Representation · Mixed

Compare the methods used in these two cases and identify the structural reason they differ: The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7. zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Question 12Representation · Transfer

Create the representation most useful for checking this result: The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7. Show the original restriction set, factored form, simplified form, and graph features such as holes or asymptotes when relevant.

Need a hint?

Label the quantities and make the same relationship visible in the new form.

Explain, compare, and diagnose

Represent and reason

Question 13Error Analysis · Mixed

A learner reports “44 hours.” but omits the original-condition check. Explain the risk before deciding whether the result is supported.

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 14Transfer · Transfer

Repair a solution that skips “Use 12=k(3)(8)412 = \frac{k(3)(8)}{4} to obtain k=2k = 2.” while solving: zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 15Modeling · Transfer

In this direct, inverse, and joint variation case, change one numerical value, solve the revised problem, and identify which parts of the original method still apply: The time tt to complete a fixed job varies inversely with the number nn of workers. If 66 workers take 1010 hours, find the time for 1515 workers.

Need a hint?

Define the unknown and its units before writing the equation.

Question 16Exit · Standard

Connect the opening situation “Model how one quantity changes when another doubles or halves.” to the algebraic structure used in the worked case. Define quantities and units before writing any equation.

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Model, transfer, and verify

Finish strong

Question 17Transfer · Transfer

Explain why the method for direct, inverse, and joint variation is valid here and name one nearby problem where it would not apply.

Need a hint?

Identify the familiar equation structure before changing any symbols.

Question 18Modeling · Transfer

Compare the conclusions of all three worked cases with this lesson outcome—Translate proportional structures into formulas with a constant parameter. Explain what remains invariant across them.

Need a hint?

Define the unknown and its units before writing the equation.

Question 19Error Analysis · Mixed

Exit check: solve and verify without referring to the displayed steps. The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7.

Need a hint?

Locate the first line that no longer preserves the original relationship.

Question 20Exit · Standard

Exit check: solve and verify without referring to the displayed steps. zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Need a hint?

Solve, classify the solution set, and verify against the original equation.

Common mistakes

Error analysis

Wrong move: Cancelling terms across addition or erasing a restriction after a factor cancels.

Why it fails: Cancellation divides an entire numerator and denominator by a common nonzero factor; separate terms are not factors.

Repair: Factor completely, state restrictions first, cancel only common factors, and check candidates in the original expression or equation.

Open-response checkA10.9

Exit check: solve and verify without referring to the displayed steps. zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.

Write a complete attempt before opening the response guide.

Attempt once to unlock the response guide

Complete a substantive attempt to unlock the protected solution and scoring criteria.

Before continuing

Exit check

  1. Exit check: solve and verify without referring to the displayed steps. The distance dd varies directly with time tt. If d=150d = 150 when t=3,t = 3, find the model and dd when t=7t = 7.
  2. Exit check: solve and verify without referring to the displayed steps. zz varies jointly with xx and yy and inversely with ww. If z=12z = 12 when x=3,y=8,x = 3, y = 8, and w=4,w = 4, find zz when x=5,y=6,x = 5, y = 6, and w=10w = 10.
Summary

What to remember

Translate proportional structures into formulas with a constant parameter. Use structure to choose the method, preserve every condition, and interpret the checked result.

  • Substitute a permitted test value into original and simplified forms, and test every equation candidate in the original denominators.
  • Inverse variation keeps the product nt constant while one quantity rises and the other falls.

Continue to unit practice →

Source & rights

Original storyboard, rights-separated references.

Public page content comes from the BetterGrades Algebra editorial storyboard supplied by the owner. Reference books named in provenance remain separate and are not copied into the application.