BetterGrades Precalculus · Unit 7 · Assessment

Unit 7 Review

A 40–50 item cumulative unit review.

unit review

50 concrete items

A 40–50 item cumulative unit review.

Assessment

Complete every required response

Item 101

Classify 3,8,13,183,8,13,18.

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Item 202

Classify 2,6,18,542,6,18,54.

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Item 303

Multiplier for 7%7\% growth.

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Item 404

Multiplier for 18%18\% decay.

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Item 505

Rate for base 1.181.18.

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Item 606

Rate for base 0.640.64.

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Item 707

Domain of 5(0.4)x5(0.4)^x.

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Item 808

Explain why this conclusion is valid: Initial 12001200 and 4%4\% growth per year. Use the foundation problem as evidence: Interpret 1200(1.04)t1200(1.04)^t.

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Item 909

HA of 4x+34^x+3.

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Item 1010

Range of 2x+1-2^x+1.

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Item 1111

Does horizontal shift move HA?

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Item 1212

Explain why this conclusion is valid: HA y=4,y=4, range (,4),(-∞,4), point (1,1)(1,1). Use the foundation problem as evidence: Analyze 32(x1)+4-3\cdot 2^(x-1)+4.

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Item 1313

12001200 grows 6%6\%.

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Item 1414

900900 decays 4%4\%.

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Item 1515

After one half-life.

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Item 1616

Explain why this conclusion is valid: A(t)=240(12)(t6)A(t)=240(\frac{1}{2})^(\frac{t}{6}). Use the foundation problem as evidence: 240240 mg with half-life 66 hours.

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Item 1717

Formula at 5%5\% annual.

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Item 1818

Periods in 77 years monthly.

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Item 1919

Monthly rate from 9%9\% nominal.

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Item 2020

Explain why this conclusion is valid: A=2000(1.005)362393.36A=2000(1.005)^36\approx 2393.36. Use the foundation problem as evidence: $2000\$2000 at 6%6\% monthly for 33 years.

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Item 2121

Initial value of 7e(3t)7e^(3t).

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Item 2222

Approximate ee.

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Item 2323

Continuous compound formula.

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Item 2424

Explain why this conclusion is valid: Continuous decay with one-unit multiplier e0.30.7408e^-0.3\approx 0.7408. Use the foundation problem as evidence: Interpret 80e(0.3t)80e^(-0.3t).

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Item 2525

Interpret b=0.81b=0.81.

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Item 2626

Good residual pattern.

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Item 2727

Can high R-squared prove causation?

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Item 2828

Meaning of K.

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Item 2929

Output at inflection.

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Item 3030

P(0)P(0) for 9001+8et\frac{900}{1+8e^-t}.

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Item 3131

Explain why this conclusion is valid: K=1000K=1000 and P(0)=100P(0)=100. Use the foundation problem as evidence: P=10001+9e(0.4t)P=\frac{1000}{1+9e^(-0.4t)}.

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Item 3232

log10(1000)log_10(1000)

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Item 3333

log2(1)log_2(1)

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Item 3434

Domain of log_b xx.

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Item 3535

Explain why this conclusion is valid: 3-3. Use the foundation problem as evidence: Evaluate log3(127)log_3(\frac{1}{27}).

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Item 3636

Domain ln(x7)ln(x-7).

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Item 3737

VA log2(x+4)log_2(x+4).

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Item 3838

Range of 4lnx+84lnx+8.

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Item 3939

Explain why this conclusion is valid: Domain x<2x<2 and VA x=2x=2. Use the foundation problem as evidence: Analyze log3(42x)log_3(4-2x).

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Item 4040

Expand log_b(xy).

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Item 4141

Condense 3lnxlny3lnx-lny.

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Item 4242

Is log(x+2)=logx+log2log(x+2)=logx+log2?

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Item 4343

Explain why this conclusion is valid: logb5+3logbxlogbylog_b5+3log_bx-log_by. Use the foundation problem as evidence: Expand logb(5x3y)log_b(\frac{5x^3}{y}).

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Item 4444

Solve2x=322^x=32

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Item 4545

Solvee(3x)=7e^(3x)=7

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Item 4646

Can 2x=42^x=-4 have real solution?

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Item 4747

Explain why this conclusion is valid: x=ln10ln32.096x=\frac{ln10}{ln}3\approx 2.096. Use the foundation problem as evidence: Solve 3x=103^x=10.

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Item 4848

Solveln(x2)=0ln(x-2)=0

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Item 4949

Factor for +1+1 on base10base-10 log scale.

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Item 5050

General time in A=A0btA=A0b^t.

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