BetterGrades Precalculus · Unit 14 · Lesson

Eliminating a parameter

Eliminate parameters while preserving interval restrictions and lost orientation information.

Textbook reading

The problem that opens the lesson

Eliminate tt from x=t+1,y=t24x=t+1, y=t^2-4 for 2t3-2\le t\le 3.

Solution

Begin by identifying the mathematical object and the information that fixes it. Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately. The relevant conditions are not optional bookkeeping: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form. Following that structure gives y=(x1)24y=(x-1)^2-4 with 1x4-1\le x\le 4; orientation follows increasing xx.

Why this works

The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Textbook reading

What this lesson is really about

Eliminating a parameter produces a Cartesian relation containing the parametric path.

Solving one equation for tt and substituting into the other is the usual method. Trigonometric parametrizations often eliminate through identities such as sin2t+cos2t=1sin^2 t+cos^2 t=1.

The point is not merely to reproduce a formula. A learner should be able to identify the quantities or geometric objects involved, explain why the relationship has its stated form, and recognize when the same idea appears in a graph, table, diagram, or model.

Textbook reading

Why the relationship works

The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing.

Textbook reading

A reliable way to work

Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately.

A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form.

After the symbolic work is complete, check the result. Depending on the lesson, this may mean substituting into an original equation, comparing coordinates, examining a graph, checking units, testing an interval, or confirming that every branch of a periodic solution has been included.

Textbook reading

What commonly goes wrong

A common error is reporting the full Cartesian curve while ignoring the restricted segment or repeated traversal.

The repair is to return to the definition and identify the first step where the invalid solution stops describing the original mathematical object. Later algebra cannot rescue a first step that changed the domain, orientation, branch, or meaning of the problem.

Textbook reading

Worked examples

Worked example 1

Eliminate tt from x=t+1,y=t24x=t+1, y=t^2-4 for 2t3-2\le t\le 3.

Solution

Begin by identifying the mathematical object and the information that fixes it. Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately. The relevant conditions are not optional bookkeeping: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form. Following that structure gives y=(x1)24y=(x-1)^2-4 with 1x4-1\le x\le 4; orientation follows increasing xx.

Why this works

The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Transfer example

Problem

Eliminate trig parameters from x=3cost,y=3sintx=3cos t,y=3sin t.

Worked development

Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. Solving one equation for tt and substituting into the other is the usual method. Trigonometric parametrizations often eliminate through identities such as sin2t+cos2t=1sin^2 t+cos^2 t=1. Then apply the conditions explicitly: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Elimination helps compare parametric and implicit representations and solve intersections.

Reasoning example

Problem

Identify a Cartesian equation that includes more than the parametric path.

Worked development

Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. Solving one equation for tt and substituting into the other is the usual method. Trigonometric parametrizations often eliminate through identities such as sin2t+cos2t=1sin^2 t+cos^2 t=1. Then apply the conditions explicitly: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Elimination helps compare parametric and implicit representations and solve intersections.

Worked example 4: quick check

Eliminate tt from x=t2,y=tx=t^2,y=t for 1t2-1\le t\le 2.

Solution

Begin by identifying the mathematical object and the information that fixes it. Eliminate t, translate the parameter interval into restrictions on xx or y, and record direction separately. The relevant conditions are not optional bookkeeping: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form. Following that structure gives x=y2x=y^2 with 1y2-1\le y\le 2.

Why this works

The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Elimination workflow. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.
Read this graph as text

Eliminating a parameter · Elimination workflow. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Eliminate parameters while preserving interval restrictions and lost orientation information.

Anchor figure · Elimination workflow

Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: The Cartesian equation may describe more points than the chosen parameter interval traces, and it usually loses orientation and timing. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Restricted parametric segment versus full Cartesian curve. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for eliminating a parameter.
Read this graph as text

Eliminating a parameter · Restricted parametric segment versus full Cartesian curve. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for eliminating a parameter. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Eliminate parameters while preserving interval restrictions and lost orientation information.

Mechanism figure · Restricted parametric segment versus full Cartesian curve

Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for eliminating a parameter.

Orientation information lost after elimination. Compare the valid path with the tempting shortcut. The figure shows why reporting the full Cartesian curve while ignoring the restricted segment or repeated traversal leads to a false conclusion.
Read this graph as text

Eliminating a parameter · Orientation information lost after elimination. Compare the valid path with the tempting shortcut. The figure shows why reporting the full Cartesian curve while ignoring the restricted segment or repeated traversal leads to a false conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Eliminate parameters while preserving interval restrictions and lost orientation information.

Comparison and error figure · Orientation information lost after elimination

Compare the valid path with the tempting shortcut. The figure shows why reporting the full Cartesian curve while ignoring the restricted segment or repeated traversal leads to a false conclusion.

Textbook reading

Application and interpretation

Elimination helps compare parametric and implicit representations and solve intersections.

A contextual answer must include units, a meaningful domain, and the assumptions that make the model plausible. An exact mathematical relationship should not be diluted into a decimal unless a measurement or comparison requires it.

Check yourself

Eliminate tt from x=t2,y=tx=t^2,y=t for 1t2-1\le t\le 2.

Write a complete attempt before opening the exact answer.

Attempt once to unlock the answer

Complete a substantive attempt before revealing the server-held answer.

Practice

Ten concrete questions

Practice 101

Eliminate tt from x=t2,y=tx=t^2,y=t for 1t2-1\le t\le 2.

Write a complete attempt before opening the exact answer.

Attempt once to unlock the answer

Complete a substantive attempt before revealing the server-held answer.

Practice 202

Eliminate trig parameters from x=3cost,y=3sintx=3cos t,y=3sin t.

Write a complete attempt before opening the exact answer.

Attempt once to unlock the answer

Complete a substantive attempt before revealing the server-held answer.

Practice 303

Identify a Cartesian equation that includes more than the parametric path.

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Practice 404

Recover parameter values for a given point.

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Practice 505

State the defining idea behind eliminating a parameter in one precise sentence.

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Practice 606

What condition or domain restriction must remain visible in the solution?

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Practice 707

Describe the most likely incorrect first step and explain why it fails.

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Practice 808

Translate the main result into a second representation: graph, diagram, table, equation, or context.

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Practice 909

Write one exact conclusion and one corresponding numerical approximation or verbal interpretation.

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Practice 1010

Explain how this lesson's idea will be used later in the course.

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Textbook reading

Lesson summary

Eliminating a parameter produces a Cartesian relation containing the parametric path.

The central condition to remember is this: A parameter may not be globally solvable as one expression, so elimination can require cases or may not produce a simple Cartesian form.

Connection forward

The next lesson keeps the parameter to study motion and average velocity.

The next lesson is Parametric motion and vector-valued position.

Source record

Original BetterGrades manuscript, rights-separated references.

  • Lippman & Rasmussen, Precalculus Vol. 2, 8.2, 8.3, 8.6, 9.4
  • Sundstrom & Schlicker, Trigonometry, Chapter 5
  • Yoshiwara, Trigonometry, Chapter 10
  • Corral, Trigonometry, 6.3-6.4

No long source passage is reproduced.