BetterGrades Precalculus · Unit 15 · Lesson

Geometric sequences

Derive and use a_n=a_1r^{n-1} and connect geometric sequences to sampled exponential functions.

Textbook reading

The problem that opens the lesson

A bacteria count is 600600 at hour 11 and triples every 22 hours. Write a sequence for counts at odd-numbered hours.

Solution

Begin by identifying the mathematical object and the information that fixes it. Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern. The relevant conditions are not optional bookkeeping: A zero term can make ratio-based recovery impossible or indicate a special sequence. Following that structure gives an=6003n1a_n=600\cdot 3^{n-1} for hours 2n12n-1.

Why this works

Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Textbook reading

What this lesson is really about

A geometric sequence has a constant ratio rr between consecutive nonzero terms.

From a1,a_1, reaching term nn requires n1n-1 multiplications, so an=a1rn1a_n=a_1 r^{n-1}. This is an exponential function sampled at integer inputs.

The point is not merely to reproduce a formula. A learner should be able to identify the quantities or geometric objects involved, explain why the relationship has its stated form, and recognize when the same idea appears in a graph, table, diagram, or model.

Textbook reading

Why the relationship works

Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs.

Textbook reading

A reliable way to work

Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern.

A zero term can make ratio-based recovery impossible or indicate a special sequence.

After the symbolic work is complete, check the result. Depending on the lesson, this may mean substituting into an original equation, comparing coordinates, examining a graph, checking units, testing an interval, or confirming that every branch of a periodic solution has been included.

Textbook reading

What commonly goes wrong

A common error is dividing terms separated by several indices and treating the result as the one-step ratio.

The repair is to return to the definition and identify the first step where the invalid solution stops describing the original mathematical object. Later algebra cannot rescue a first step that changed the domain, orientation, branch, or meaning of the problem.

Textbook reading

Worked examples

Worked example 1

A bacteria count is 600600 at hour 11 and triples every 22 hours. Write a sequence for counts at odd-numbered hours.

Solution

Begin by identifying the mathematical object and the information that fixes it. Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern. The relevant conditions are not optional bookkeeping: A zero term can make ratio-based recovery impossible or indicate a special sequence. Following that structure gives an=6003n1a_n=600\cdot 3^{n-1} for hours 2n12n-1.

Why this works

Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Transfer example

Problem

Find rr from two consecutive terms.

Worked development

Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. From a1,a_1, reaching term nn requires n1n-1 multiplications, so an=a1rn1a_n=a_1 r^{n-1}. This is an exponential function sampled at integer inputs. Then apply the conditions explicitly: A zero term can make ratio-based recovery impossible or indicate a special sequence. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Geometric sequences model compound growth, decay, rebounds, dilution, and repeated scaling.

Reasoning example

Problem

Find rr across a multi-step index gap.

Worked development

Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern. In this example, the first useful move is to make the defining structure visible rather than to search for a memorized answer. From a1,a_1, reaching term nn requires n1n-1 multiplications, so an=a1rn1a_n=a_1 r^{n-1}. This is an exponential function sampled at integer inputs. Then apply the conditions explicitly: A zero term can make ratio-based recovery impossible or indicate a special sequence. Finish by checking the result in a second representation and explaining what the result means.

Interpretation

Geometric sequences model compound growth, decay, rebounds, dilution, and repeated scaling.

Worked example 4: quick check

Find a8a_8 for 5,10,20,5,-10,20,...

Solution

Begin by identifying the mathematical object and the information that fixes it. Use indexed terms to form r^{difference in indices}, solve for r, and verify sign and magnitude against the term pattern. The relevant conditions are not optional bookkeeping: A zero term can make ratio-based recovery impossible or indicate a special sequence. Following that structure gives 640-640.

Why this works

Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Multiplicative term bars. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.
Read this graph as text

Geometric sequences · Multiplicative term bars. Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1r^{n-1} and connect geometric sequences to sampled exponential functions.

Anchor figure · Multiplicative term bars

Follow the foundation example from its given information to the conclusion. The labels identify the mathematical feature that makes the result valid: Ratios may be positive, negative, fractional, or greater than one, creating growth, decay, or alternating signs. The calculation and the representation should agree, so a graph, diagram, table, or substitution check should support the same conclusion.

Sampled exponential graph. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for geometric sequences.
Read this graph as text

Geometric sequences · Sampled exponential graph. Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for geometric sequences. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1r^{n-1} and connect geometric sequences to sampled exponential functions.

Mechanism figure · Sampled exponential graph

Read the numbered reasoning path in order. Each stage preserves the quantities, restrictions, or structural conditions needed for geometric sequences.

Alternating-sign geometric sequence. Compare the valid path with the tempting shortcut. The figure shows why dividing terms separated by several indices and treating the result as the one-step ratio leads to a false conclusion.
Read this graph as text

Geometric sequences · Alternating-sign geometric sequence. Compare the valid path with the tempting shortcut. The figure shows why dividing terms separated by several indices and treating the result as the one-step ratio leads to a false conclusion. The figure uses concrete points, curves, arrows, intervals, or matrix structure instead of relying on color alone.

Labels, point shapes, line styles, arrows, and position carry the mathematical meaning; color is supplementary.

Why it matters: Use the mathematical objects in this figure to support the lesson outcome: Derive and use a_n=a_1r^{n-1} and connect geometric sequences to sampled exponential functions.

Comparison and error figure · Alternating-sign geometric sequence

Compare the valid path with the tempting shortcut. The figure shows why dividing terms separated by several indices and treating the result as the one-step ratio leads to a false conclusion.

Textbook reading

Application and interpretation

Geometric sequences model compound growth, decay, rebounds, dilution, and repeated scaling.

A contextual answer must include units, a meaningful domain, and the assumptions that make the model plausible. An exact mathematical relationship should not be diluted into a decimal unless a measurement or comparison requires it.

Check yourself

Find a8a_8 for 5,10,20,5,-10,20,...

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Attempt once to unlock the answer

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Practice

Ten concrete questions

Practice 101

Find a8a_8 for 5,10,20,5,-10,20,...

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Practice 202

Find rr from two consecutive terms.

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Practice 303

Find rr across a multi-step index gap.

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Practice 404

Analyze negative and fractional ratios.

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Practice 505

State the defining idea behind geometric sequences in one precise sentence.

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Practice 606

What condition or domain restriction must remain visible in the solution?

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Practice 707

Describe the most likely incorrect first step and explain why it fails.

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Practice 808

Translate the main result into a second representation: graph, diagram, table, equation, or context.

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Practice 909

Write one exact conclusion and one corresponding numerical approximation or verbal interpretation.

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Practice 1010

Explain how this lesson's idea will be used later in the course.

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Textbook reading

Lesson summary

A geometric sequence has a constant ratio rr between consecutive nonzero terms.

The central condition to remember is this: A zero term can make ratio-based recovery impossible or indicate a special sequence.

Connection forward

The next lesson studies general iteration and long-run behavior of recurrences.

The next lesson is Recurrence, iteration, and discrete dynamical models.

Source record

Original BetterGrades manuscript, rights-separated references.

  • Stitz & Zeager, Precalculus, Chapter 9
  • University of Washington Precalculus, discrete-model problems
  • AP Precalculus framework, sequence and model connections

No long source passage is reproduced.