BetterGrades Algebra · Unit A3 · Lesson
Solving linear inequalities
Apply equation-style operations while tracking order and representing the result as a set.
Start here
Find all values that keep a total under a limit.
Use the opening situation and three distinct, fully solved cases to learn solving linear inequalities as a connected mathematical idea rather than a memorized slogan.
Prerequisite check
- State the earlier definition or operation most directly connected to: Apply equation-style operations while tracking order and representing the result as a set.
- Classify the object in the worked prompt before choosing an operation: Solve and write the solution in interval notation.
- Name the check you would use to reject an answer with the wrong sign, domain, units, endpoint, or graph behavior.
Explanation
Apply equation-style operations while tracking order and representing the result as a set. The lesson is about a particular mathematical decision, not a keyword or a decorative notation pattern. In solving linear inequalities, first identify the object being studied and the information the answer must contain. Then mark the conditions that cannot be lost: these may include sign, endpoint inclusion, grouping, units, denominator restrictions, real-number domain, or the difference between an exact value and an approximation. A useful solution explains why its first move matches that structure.
Find all values that keep a total under a limit. This opening is useful because it forces the quantities to acquire meaning before symbols compress them. Name the changing and fixed quantities, define any reference value or input interval, and decide what would count as a plausible result. An estimate, sign prediction, graph feature, or domain statement made before calculation becomes an independent check afterward. Without that prediction, algebra can be internally tidy while answering the wrong contextual question.
Consider the worked problem: Solve and write the solution in interval notation. Begin with this justified move: Subtract from both sides to obtain . Next, divide by and reverse the order symbol. Finally, check the boundary and one value on each side in the original inequality. Each line should preserve the relevant relationship or deliberately produce candidates that are later tested. Skipping the middle line may hide the exact sign, factor, interval, or restriction on which the conclusion depends.
The result is or ∞). The endpoint is included because equality is allowed, and negative division reverses the direction of the truth set. A textbook answer does not stop at the last symbol. It states what the result means, includes units or set notation where required, and distinguishes a verified solution from a candidate. The original statement remains the final authority whenever the method includes a one-way operation, denominator clearing, squaring, graph estimation, regression, or numerical approximation.
Use an inequality, interval notation, and a number-line description; each must show the same endpoints, inclusion, and direction. Changing representation is useful only when it exposes information rather than duplicating decoration. A table may reveal constant difference or ratio, a graph may reveal intersections or extrema, interval notation may compress a truth set, and factored or vertex form may expose a feature hidden in expanded form. The second representation must preserve the same values, restrictions, units, endpoints, and conclusions as the first.
An equation identifies values that make two expressions equal; an inequality identifies values that place one expression above, below, inside, or outside a boundary. That difference changes the shape of an answer. A linear equation often ends at one value, while a linear inequality usually ends with an interval or union of intervals. The answer must therefore name set, not merely a boundary number. Test points reveal which side of a boundary belongs to the truth set, and endpoint notation records whether equality is permitted. For solving linear inequalities, connect this principle directly to the stated outcome: Apply equation-style operations while tracking order and representing the result as a set.
Inequality operations preserve order only when the transformation preserves direction. Adding the same value to both sides translates both quantities equally. Multiplying by a positive number rescales without changing which is larger. Multiplying by a negative number also reflects the number line, so the order reverses. The familiar instruction to reverse the symbol is a consequence of that reflection, not an isolated sign rule. A quick numerical comparison before and after scaling makes the reason visible. For solving linear inequalities, connect this principle directly to the stated outcome: Apply equation-style operations while tracking order and representing the result as a set.
Distance statements unify absolute-value equations and inequalities. The expression |x a| measures the distance from to the center a. Equality to a nonnegative radius produces two boundary points, a less-than condition produces an interval around the center, and a greater-than condition produces two exterior rays. Literal equations extend the same preservation principle to formulas: isolate the requested quantity without changing the relationship, carry units, and state any nonzero divisor required by the rearrangement. For solving linear inequalities, connect this principle directly to the stated outcome: Apply equation-style operations while tracking order and representing the result as a set.
A common failure is: Reporting only the boundary value after solving an inequality. A boundary separates regions but does not by itself state which region satisfies the condition or whether the endpoint is included. The repair is concrete: Write the solution as an inequality or interval, then test one interior point in the original condition. In the worked case, use the repair by checking “ or ∞).” against the original problem rather than trusting that the final line merely looks familiar.
The endpoint is included because equality is allowed, and negative division reverses the direction of the truth set. That conclusion is the bridge to the next lesson: the method matters because it preserves meaning while the representation changes. A durable summary therefore has four parts—classify the object, state the conditions, carry out one justified step at time, and perform an independent check. If any of those parts is missing, return to the original quantities before adding more algebra.
Definitions and conditions
- Solving linear inequalities
- Apply equation-style operations while tracking order and representing the result as a set.Use the term only when the object satisfies the structural and domain conditions developed in this lesson.
- truth set
- The set of every allowed value that makes a statement true.A complete answer includes endpoint inclusion and any domain restrictions.
- equivalent inequality
- An inequality with exactly the same truth set as the original.Negative scaling reverses the order symbol because it reverses order.
- boundary value
- A value where the truth of an inequality can change.The boundary is included only when equality is part of the condition and the expression is defined there.
Worked examples
Worked Example 1
Solve and write the solution in interval notation.
- Subtract from both sides to obtain .
- Divide by and reverse the order symbol.
- Check the boundary and one value on each side in the original inequality.
Answer or ∞).
The endpoint is included because equality is allowed, and negative division reverses the direction of the truth set.
Worked Example 2
Solve and graph the solution set.
- Multiply both sides by positive so the order remains unchanged: .
- Add and divide by to obtain .
- Check in the original inequality and exclude the boundary .
Answer or ∞).
Positive scaling preserves order, and the strict boundary is shown with an open endpoint.
Worked Example 3
A delivery company charges plus per mile. For what distances is the charge at most ?
- Model the limit by with .
- Subtract and divide by to obtain .
- Intersect the algebraic result with the contextual domain .
Answer miles.
The contextual domain removes negative distances from the algebraic truth set.
20 practice questions
Recall and read the structure
Warm-up
Classify the mathematical object and requested action in this lesson case: Solve and write the solution in interval notation.
Need a hint?
Recall the named definition or perform a direct substitution before choosing an operation.
State the central definition behind this outcome: Apply equation-style operations while tracking order and representing the result as a set.
Need a hint?
Recall the named definition or perform a direct substitution before choosing an operation.
Before calculating, list every sign, endpoint, unit, grouping, or domain condition that can affect: Solve and write the solution in interval notation.
Need a hint?
State what must remain true, then connect that condition to the equation.
Explain why this opening move is valid: Subtract from both sides to obtain .
Need a hint?
State what must remain true, then connect that condition to the equation.
Build accuracy one step at a time
Core practice
Solve and write the solution in interval notation.
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
Solve and graph the solution set.
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
A delivery company charges plus per mile. For what distances is the charge at most ?
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
Verify the proposed result “ or ∞).” against the original statement.
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
Complete the calculation after “Multiply both sides by positive so the order remains unchanged: .” in this problem: Solve and graph the solution set.
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
Name and justify the most efficient first move, then solve: A delivery company charges plus per mile. For what distances is the charge at most ?
Need a hint?
Write one equality-preserving step at a time and keep signs and grouping visible.
Compare the methods used in these two cases and identify the structural reason they differ: Solve and graph the solution set. A delivery company charges plus per mile. For what distances is the charge at most ?
Need a hint?
Label the quantities and make the same relationship visible in the new form.
Create the representation most useful for checking this result: Solve and graph the solution set. Use an inequality, interval notation, and a number-line description; each must show the same endpoints, inclusion, and direction.
Need a hint?
Label the quantities and make the same relationship visible in the new form.
Explain, compare, and diagnose
Represent and reason
A learner reports “ or ∞).” but omits the original-condition check. Explain the risk before deciding whether the result is supported.
Need a hint?
Locate the first line that no longer preserves the original relationship.
Repair a solution that skips “Subtract and divide by to obtain .” while solving: A delivery company charges plus per mile. For what distances is the charge at most ?
Need a hint?
Identify the familiar equation structure before changing any symbols.
In this solving linear inequalities case, change one numerical value, solve the revised problem, and identify which parts of the original method still apply: Solve and write the solution in interval notation.
Need a hint?
Define the unknown and its units before writing the equation.
Connect the opening situation “Find all values that keep a total under a limit.” to the algebraic structure used in the worked case. Define quantities and units before writing any equation.
Need a hint?
Solve, classify the solution set, and verify against the original equation.
Model, transfer, and verify
Finish strong
Explain why the method for solving linear inequalities is valid here and name one nearby problem where it would not apply.
Need a hint?
Identify the familiar equation structure before changing any symbols.
Compare the conclusions of all three worked cases with this lesson outcome—Apply equation-style operations while tracking order and representing the result as a set. Explain what remains invariant across them.
Need a hint?
Define the unknown and its units before writing the equation.
Exit check: solve and verify without referring to the displayed steps. Solve and graph the solution set.
Need a hint?
Locate the first line that no longer preserves the original relationship.
Exit check: solve and verify without referring to the displayed steps. A delivery company charges plus per mile. For what distances is the charge at most ?
Need a hint?
Solve, classify the solution set, and verify against the original equation.
Error analysis
Wrong move: Reporting only the boundary value after solving an inequality.
Why it fails: A boundary separates regions but does not by itself state which region satisfies the condition or whether the endpoint is included.
Repair: Write the solution as an inequality or interval, then test one interior point in the original condition.
A3.2Exit check: solve and verify without referring to the displayed steps. A delivery company charges plus per mile. For what distances is the charge at most ?
Write a complete attempt before opening the response guide.
Attempt once to unlock the response guide
Complete a substantive attempt to unlock the protected solution and scoring criteria.
Exit check
- Exit check: solve and verify without referring to the displayed steps. Solve and graph the solution set.
- Exit check: solve and verify without referring to the displayed steps. A delivery company charges plus per mile. For what distances is the charge at most ?
What to remember
Apply equation-style operations while tracking order and representing the result as a set. Use structure to choose the method, preserve every condition, and interpret the checked result.
- Test a value inside the proposed set, a value outside it, and every boundary value in the original condition.
- The endpoint is included because equality is allowed, and negative division reverses the direction of the truth set.
Source & rights
Original storyboard, rights-separated references.
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