Calculus I · Unit 3A · lesson

Integration by Parts

Concept

Learning objectives

Derive the formula from the product rule, choose uu and dvdv, and use the method on products and disguised products.

Integration by Parts

Explanation

Integration by parts redistributes a product

Integration by parts comes from integrating the product rule. It is useful when an integrand is a product whose factors become easier in different directions: one factor simplifies when differentiated, while the other can be integrated. The formula udv=uvvdu\int u\,dv=uv-\int v\,du does not eliminate work automatically; it trades the original integral for a hopefully simpler one.

Choosing uu and dvdv is therefore the central judgment. Logarithmic and inverse-trigonometric factors are usually chosen as uu because they are difficult to integrate directly but manageable to differentiate. Polynomial factors often improve when differentiated. After applying the formula, compare the new integral with the old one. If it is more complicated, reconsider the choice rather than marching deeper into algebraic wilderness out of loyalty to the first idea.

From the product rule,

(uv)=uv+uv.(uv)'=u'v+uv'.

Integrating and rearranging gives

udv=uvvdu.\boxed{\int u\,dv=uv-\int v\,du}.
Guided walkthrough

Polynomial times exponential

Evaluate xexdx\int xe^x\,dx.

Answer reveal

Worked solution

Write a real attempt before opening the supplied answer.

Worked example

A disguised product

To integrate lnx\ln x, write lnx1\ln x\cdot1. Let u=lnxu=\ln x and dv=dxdv=dx. Then

lnxdx=xlnx1dx=xlnxx+C.\int\ln x\,dx=x\ln x-\int1\,dx=x\ln x-x+C.
Interactive checku3a-parts-01

Evaluate xexdx\int xe^x\,dx.

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Show hint

Let u=xu=x and dv=exdxdv=e^x dx.

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Integration by parts from the product rule. Show product rule rearranged and integrated, with u and dv roles.
Read this graph as text

Integration by parts from the product rule. The product rule is rearranged to produce integral u dv = uv - integral v du. Show product rule rearranged and integrated, with u and dv roles. Do not present LIATE as a theorem; it is a heuristic.

Every relationship in integration by parts from the product rule uses written labels together with distinct line styles, markers, or fill patterns; color is never the only carrier of meaning.

Why it matters: Show product rule rearranged and integrated, with u and dv roles.

Visual study

Integration by parts from the product rule. Show product rule rearranged and integrated, with u and dv roles.

After the explanation

Use the section idea

Reading lens

Choose an integration method from the integrand's structure, then verify the result by differentiation.

Mental model

Substitution reverses a chain rule, parts reverses a product rule, and algebraic or trigonometric rewrites expose a recognizable derivative pattern.

Decision

Simplify first; look for an inner derivative; then consider parts, identities, trigonometric substitution, or partial fractions in a deliberate order.

Common trap

Choosing a method by surface appearance, transforming only part of the differential, or accepting a more complicated integral than the one you started with.

Check yourself

Can you name the derivative rule being reversed and differentiate the final answer back to the integrand?

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Original instruction with traceable references.

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